-500x^2+10000=0

Solution for -500x^2+10000=0 equation:

-500x^2+10000=0

a = -500; b = 0; c = +10000;
Δ = b2-4ac
Δ = 02-4·(-500)·10000
Δ = 20000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20000000}=\sqrt{4000000*5}=\sqrt{4000000}*\sqrt{5}=2000\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2000\sqrt{5}}{2*-500}=\frac{0-2000\sqrt{5}}{-1000}
=-\frac{2000\sqrt{5}}{-1000}
=-\frac{2\sqrt{5}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2000\sqrt{5}}{2*-500}=\frac{0+2000\sqrt{5}}{-1000}
=\frac{2000\sqrt{5}}{-1000}
=\frac{2\sqrt{5}}{-1}
$